Question 1.
If some distance is traveled at a speed of ‘x’ km/h and the same distance is traveled at a speed of ‘y’ km/h. Then, the average speed during the whole journey:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgMB3Akx0TUmtRZ_0_hQn-hWnHfkys-3ihAjOK6z7Qvv_O2WmnHF8ycTM8JwWpTF_IFNj4GO7bnQRTQ4kybsb8nBh1ZXRf-uL8N69kn4dKF7FLrovL9ElfKEcPwaQRWhnfFr2wM9xtyUp0/s200/1.png)
Example: If the distance between Goa to Delhi is 750 km. A person goes at a speed of 60 km/h and returns at a speed of 40 km/h. Find the average speed.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgmqCUZDvf8V1LmfYRoPT0Ux62XdB4o2-hBmBQ0DEkJjAFk46z65y46x4dn107eNvGABR0LxPe3KpTANIcSco1bhltV7XKDLnuvzifRP9ThKP_Ia2b2npm4-NwbJCKUYN9pcDlWkcmY5NY/s320/2.png)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image002.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgMB3Akx0TUmtRZ_0_hQn-hWnHfkys-3ihAjOK6z7Qvv_O2WmnHF8ycTM8JwWpTF_IFNj4GO7bnQRTQ4kybsb8nBh1ZXRf-uL8N69kn4dKF7FLrovL9ElfKEcPwaQRWhnfFr2wM9xtyUp0/s200/1.png)
Example: If the distance between Goa to Delhi is 750 km. A person goes at a speed of 60 km/h and returns at a speed of 40 km/h. Find the average speed.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgmqCUZDvf8V1LmfYRoPT0Ux62XdB4o2-hBmBQ0DEkJjAFk46z65y46x4dn107eNvGABR0LxPe3KpTANIcSco1bhltV7XKDLnuvzifRP9ThKP_Ia2b2npm4-NwbJCKUYN9pcDlWkcmY5NY/s320/2.png)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image002.gif)
Question 2.
If the distance is different than average speed is:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiIN7AGRCXfaCSVEm2Q74ch5dAr8EZg09xC61WO3r3j1hcCQaUVpfKfWPZ-pyd9vnvM-Z9hiiJMJohDh0DGIXWt6XI0pWsJaP2d8ISMJjqgG0i9XOPOGkLWZia4hchN_cGkXtXlO5HaZuQ/s320/3.png)
Example: If the speed of the bus is 30 km/h for the 90 km and 35 km/h for the distance of 70 km. Find the average distance.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiIN7AGRCXfaCSVEm2Q74ch5dAr8EZg09xC61WO3r3j1hcCQaUVpfKfWPZ-pyd9vnvM-Z9hiiJMJohDh0DGIXWt6XI0pWsJaP2d8ISMJjqgG0i9XOPOGkLWZia4hchN_cGkXtXlO5HaZuQ/s320/3.png)
Example: If the speed of the bus is 30 km/h for the 90 km and 35 km/h for the distance of 70 km. Find the average distance.
Solution:
If the speed ratio between P and Q is a:b, so to cover the same distance the ratio between times taken by them will be
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjQ34rq1ndjYAZU8iklxHRhBafvgM29V1_3IIDbryYYtKkeJCsGhyphenhyphenBNq_4JWkWYntZzc7NWQdDosAZO6-rUuTEhrlSuLlQc_UHhHp_8sKJvkF1Ob1mYuneTcSx0JOxK3RJ8ArnqACqzphQ/s1600/5.png)
Example: The ratio between the speed of two cars is 6:8. If the second car covers a certain distance in 9 hours, then find the time taken by the first car to cover the same distance.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj_kx_0JGVi8RpraNyMWSSBZXN8CEPd-EOsWuwmDSlYf90IBBZ_mwp_T8AlUlNNlC-3-oldb8ztKszGOyucTQ-uyhJHRd0cpjXbOqSGtWLJedGQuYg1iITxt1ocQlChO_FGMZqzGnoYkpM/s320/6.png)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjQ34rq1ndjYAZU8iklxHRhBafvgM29V1_3IIDbryYYtKkeJCsGhyphenhyphenBNq_4JWkWYntZzc7NWQdDosAZO6-rUuTEhrlSuLlQc_UHhHp_8sKJvkF1Ob1mYuneTcSx0JOxK3RJ8ArnqACqzphQ/s1600/5.png)
Example: The ratio between the speed of two cars is 6:8. If the second car covers a certain distance in 9 hours, then find the time taken by the first car to cover the same distance.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj_kx_0JGVi8RpraNyMWSSBZXN8CEPd-EOsWuwmDSlYf90IBBZ_mwp_T8AlUlNNlC-3-oldb8ztKszGOyucTQ-uyhJHRd0cpjXbOqSGtWLJedGQuYg1iITxt1ocQlChO_FGMZqzGnoYkpM/s320/6.png)
Question 4.
To find the time of halts when the speed with stoppages is
a km/h and speed without stoppages b km/h:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhcFZH25dEbi1TS4qs1HWpbod_gZMXoQVPJkQU3bGdgVtnFA-4Xj84gP1pDiSZeLdrx54hbzSAb_pjwYlbcaOry3Uc2aelMnpf2nfVCZqBu2ZAt-Jf2b1p1FvziwbHQs9Fc2vuAPa_MDqo/s320/7.png)
Example:A man running on a road without any stoppage at an average speed of 100 km /hr, and he covers the same distance with stoppage at an average speed of 80 km/hr. How many minutes per hour does boy stop?
Solution:
a km/h and speed without stoppages b km/h:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhcFZH25dEbi1TS4qs1HWpbod_gZMXoQVPJkQU3bGdgVtnFA-4Xj84gP1pDiSZeLdrx54hbzSAb_pjwYlbcaOry3Uc2aelMnpf2nfVCZqBu2ZAt-Jf2b1p1FvziwbHQs9Fc2vuAPa_MDqo/s320/7.png)
Example:A man running on a road without any stoppage at an average speed of 100 km /hr, and he covers the same distance with stoppage at an average speed of 80 km/hr. How many minutes per hour does boy stop?
Solution:
Question 5.
A man walks at x/y speed of his actual speed reaches his destination z mint later. To cover this distance actual time is:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhQltwlQNgYp2m5pwUjKwkBc5mgFgFvRuUXLP1-Eai8LI1DZDqNLFeoi_b612iRuSFpMOUruocW_onVsN-ZjCQWrXPnXvQXN2P-Qn20tZzt2FTKcWinZppP9Eh9gVplA6OOiQDqkIo-Eus/s200/9.png)
Example: Walking at 3/4th of usual speed, A person is late by 10 minutes. Find the usual time.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgL94YeUxjN4HDv6dQbi4iVIcUWrmZagdhZtAUX4AzHeb2o42E3fXDZSFnMtMAOFQEcoYtcyfgCYXoxsycLlljDPQ4PgE1K0iVQbWS8n1XagRb-txnj8x9XQVgDZ5q1-0pHwy5SBMLQTKs/s320/10.png)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image028.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhQltwlQNgYp2m5pwUjKwkBc5mgFgFvRuUXLP1-Eai8LI1DZDqNLFeoi_b612iRuSFpMOUruocW_onVsN-ZjCQWrXPnXvQXN2P-Qn20tZzt2FTKcWinZppP9Eh9gVplA6OOiQDqkIo-Eus/s200/9.png)
Example: Walking at 3/4th of usual speed, A person is late by 10 minutes. Find the usual time.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgL94YeUxjN4HDv6dQbi4iVIcUWrmZagdhZtAUX4AzHeb2o42E3fXDZSFnMtMAOFQEcoYtcyfgCYXoxsycLlljDPQ4PgE1K0iVQbWS8n1XagRb-txnj8x9XQVgDZ5q1-0pHwy5SBMLQTKs/s320/10.png)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image028.gif)
Question 6.
A man walks at x/y speed of his actual speed reaches his destination z mint early. To cover this distance actual time is:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEimA5Vw-chNPobSAR7RPSIRXOcRo3Sc1WsqRvhiEXd33tdlj0FfgSCeAxmziPlL6op1JXZH8eVE7jXTbhrVYzkG9S6KQjcixKpvC3MjTD4ku1LDASyYJWMjpNRlref5HDr5y-l62EoFVgc/s200/11.png)
Example: Walking at 6/5th of usual speed, A person reached early by 5 minutes. Find the usual time.
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgMWA0ovb1s7UKqTn97OpEsK44OK2HpxNwLX6zBQn0HST8oa5hlzPFmPssUVYbnSZpmmFAxwzq5gagz5FdcSQ8ykcwE8_1oY5J6tPEnVB1aK8C2570zMwS2Wg6qJPHe-j7Ixc1fgov_TKk/s320/12.png)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image036.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEimA5Vw-chNPobSAR7RPSIRXOcRo3Sc1WsqRvhiEXd33tdlj0FfgSCeAxmziPlL6op1JXZH8eVE7jXTbhrVYzkG9S6KQjcixKpvC3MjTD4ku1LDASyYJWMjpNRlref5HDr5y-l62EoFVgc/s200/11.png)
Example: Walking at 6/5th of usual speed, A person reached early by 5 minutes. Find the usual time.
Solution:
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image036.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgMWA0ovb1s7UKqTn97OpEsK44OK2HpxNwLX6zBQn0HST8oa5hlzPFmPssUVYbnSZpmmFAxwzq5gagz5FdcSQ8ykcwE8_1oY5J6tPEnVB1aK8C2570zMwS2Wg6qJPHe-j7Ixc1fgov_TKk/s320/12.png)
Question 7.
A & B start moving towards each other at same time. After meeting each other, they reach their destinations after ‘a’ and ‘b’ hrs respectively.
A’s Speed: B’s Speed = √b: √a
Example: Two trains, one from Delhi to Pune and the other from Pune to Delhi, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 9 hours respectively. What will be the ratio of their speeds?
Solution:
A:B = √b : √a
A:B = √9 : √4
A:B = 3:2
A’s Speed: B’s Speed = √b: √a
Example: Two trains, one from Delhi to Pune and the other from Pune to Delhi, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 9 hours respectively. What will be the ratio of their speeds?
Solution:
A:B = √b : √a
A:B = √9 : √4
A:B = 3:2
Question 8.
A man/train leaves from A at x1 AM and reaches Q at x2 AM. Another man/train leaves from Q at y1 AM and reaches P at y2 PM. They will meet:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg4HjgHg9KlaXQXPLVTjOn2aNuggVEYjk6l_QhNU052hceBkMzak6roJDc_wEX5saMQ2pmx-sPUiOKgqd8JKJ_lbJM2aA_RP32POdSLkfh4iNK2gmTlkhCphYRJ1DDbXkF8dxWbZI3i2j4/s320/13.png)
Example: A train leaves from Bombay at 6:30 AM and reaches Jaipur at 10:30 AM. Another train leaves from Jaipur at 9 AM and reaches Delhi at 12:30 PM. When they will meet?
Solution:
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg4HjgHg9KlaXQXPLVTjOn2aNuggVEYjk6l_QhNU052hceBkMzak6roJDc_wEX5saMQ2pmx-sPUiOKgqd8JKJ_lbJM2aA_RP32POdSLkfh4iNK2gmTlkhCphYRJ1DDbXkF8dxWbZI3i2j4/s320/13.png)
Example: A train leaves from Bombay at 6:30 AM and reaches Jaipur at 10:30 AM. Another train leaves from Jaipur at 9 AM and reaches Delhi at 12:30 PM. When they will meet?
Solution:
If the distance between A to B is D km. Two persons P and Q travel from points A to B, with the speed of 'a' and 'b' respectively and Q reaches B first, returns immediately and meets P at X, then
Distance traveled by P (from points A to X) =![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image052.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgyu0_K8WaR-GKxF4Q7ccMp26wbLvf2jARszc0tcDVs9LHH1MmbCjO2VV3z6OOixr0qMKFRrTtsJVZz3iMvwFmQdG0jhSCvb2UR40RcBXCWd5UsN-2ghMiFJ-HA4RDsEx1YE0ssgOgPiEc/s1600/Capture.PNG)
Example: Suhail and Meetu travel from point A to B, a distance of 48 km, at 7 km/ h and 9 km/ h, respectively. Meetu reaches B first and returns immediately and meets Suhail at R. Find the distance from points A to R.
Solution:
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image054.gif)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image056.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhF82SRnkTyL2Ab8rROg6EJRsKIWLhHp3bAX9lpnbUoDXPfN9Jpgakie-eg57XefNVHVDj8lsW_l1_Fa0jJK2uHwxiyo_CBNWVp4LzpY_79B56IN3es2ioCQvCR9BDZmuaRDKLWeQN1lLE/s400/15.png)
Distance traveled by P (from points A to X) =
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image052.gif)
Example: Suhail and Meetu travel from point A to B, a distance of 48 km, at 7 km/ h and 9 km/ h, respectively. Meetu reaches B first and returns immediately and meets Suhail at R. Find the distance from points A to R.
Solution:
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image054.gif)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image056.gif)
![](file:///C:/Users/MYPC~1/AppData/Local/Temp/msohtmlclip1/01/clip_image058.gif)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhF82SRnkTyL2Ab8rROg6EJRsKIWLhHp3bAX9lpnbUoDXPfN9Jpgakie-eg57XefNVHVDj8lsW_l1_Fa0jJK2uHwxiyo_CBNWVp4LzpY_79B56IN3es2ioCQvCR9BDZmuaRDKLWeQN1lLE/s400/15.png)
Question 10.
Relative Speed:
(i). If two objects are moving in the same direction with the speeds of a km/h and b km/h then their relative speed is |a‐b|.
(ii). If two objects are moving in opposite direction with the speeds of a km/h and b km/h then their relative speed is (a+b).
Example: 2 men A and B started from a place P walking at 4 km/h and 3 km/h respectively. How many km will they be a part at the end of 1 hour?
(i) If they walk in the same direction.
(ii) If they walk in opposite direction.
Solution:
(i): Relative speed = Ia-bI
= I 4-5 I
= 1 km/h
(i). If two objects are moving in the same direction with the speeds of a km/h and b km/h then their relative speed is |a‐b|.
(ii). If two objects are moving in opposite direction with the speeds of a km/h and b km/h then their relative speed is (a+b).
Example: 2 men A and B started from a place P walking at 4 km/h and 3 km/h respectively. How many km will they be a part at the end of 1 hour?
(i) If they walk in the same direction.
(ii) If they walk in opposite direction.
Solution:
(i): Relative speed = Ia-bI
= I 4-5 I
= 1 km/h
(ii): Relative speed = a+b
= 4+5
= 9 km/h
= 4+5
= 9 km/h