Q. (1-5) Study the given table carefully to answer the following questions.
==>> Must read - Data Interpretation Guide
Field Name | Shape | Side (in m) | Base (in m) | Height (in m) | Radius (in m) | Cost of flooring (in Rs. per sq. metre) | Cost of fencing (in Rs. per m) |
|---|---|---|---|---|---|---|---|
A | Triangle | 16 | 12 | 50 | 20 | ||
B | Rectangle | 10 × 20 | 30 | ||||
C | Square | 15 | 40 | 18 | |||
D | Parallelogram | 20 | 12 | 60 | 25 | ||
E | Circle | 10 | 45 | 22 |
Q1. What is the cost of flooring of A?
a) Rs.4000 b) Rs.4600 c) Rs.4800
d) Rs.5000 e) Rs.4400
Q2.What is the difference between the cost of fencing of C and that of B?
a) Rs.180 b) Rs.120 c) Rs.240
d) Rs.360 e) Rs.480
Q3. What is the ratio of the cost of flooring to that of fencing of field D?
a) 4 : 1 b) 6 : 1 c) 8 : 1
d) 9 : 1 e) 5 : 1
Q4. The cost of fencing of field E is approximately what percent of the cost of flooring of field C?
a) 10.5% b) 19.46% c) 18.71%
d) 15.36% e) 13.82%
Q5. The cost of fencing of field C is what percent of the cost of fencing of field D?
a) 87.54% b) 67.5% c) 72.13%
d) 54.36% e) 46.5%
==>> Must read - Data Interpretation Guide
Solution
1. Option C
A is a triangle
So, area of A = 1/2
So, cost of flooring of A = 96 × 50 = Rs.4800
2. Option A
Perimeter of B = 2 (10 + 20) = 60 m
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 - 900 = Rs.180
3. Option D
Area of D = Base × Height
= 20 × 12 = 240
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1
4. Option D
Perimeter of E = 2πr = 2 × 22 / 7
Cost of fencing of E = 440 / 7 × 22 = Rs.1382.85
Area of C = (15)2 = 225m2
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85
= 15.36% of flooring cost of C.
5. Option B
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080 / 1600 × 100 = 67.5%